What is the nature of roots of quadratic equation √ 3x2 2 √ 3x+ √ 3 0?

1 Answer. Roots of the equation are real and equal.

What is the nature of the roots of the quadratic equation 3x2?

1 Answer. It's seen that D = 0 and hence, the given equation has only 1 real and equal root.

What is the nature of roots of the quadratic equation 3x2 4x 2 0?

Answer: The roots of the equation 3x² - 4x - 2 = 0 are real and unequal.

What is the nature of the roots of the quadratic equation 4x² 4 √ 3x 3 0?

Answer: The roots of the equation are Real and Equal.

What are the nature of roots of quadratic equation?

We can see, the discriminant of the given quadratic equation is positive but not a perfect square. Hence, the roots of a quadratic equation are real, unequal, and irrational.

Q5 | Find the roots of the quadratic equation :- √3x2 – 2√2x – 2√3 = 0 | Quadratic Equations

What is the nature of roots of the quadratic equation 2x2 √ 5x 1 0?

Hence, the roots of the quadratic equation 2x² – √5x + 1 = 0 are imaginary.

What is the nature of the roots of the quadratic equation 5x2 2x 3 0?

So, the root are imaginary , i.e. it has two non real roots.

What is the nature of the roots of the quadratic equation 2x2 6x 3 0?

As b² – 4ac > 0, Hence, there are distinct real roots exist for this equation, 2x² – 6x + 3 = 0.

What is the nature of roots of the quadratic equation 4x2 − 12x − 9 0?

What is the nature of roots of the quadratic equation 4x² – 12x – 9 = 0? Since D > 0, therefore, roots of the given equation are real and unequal.

What will be the nature of roots of quadratic equation 2x 2 4x 7 0?

1 Answer. Hence, roots of the quadratic equation are real and unequal.

What is the nature of the roots of the quadratic equation 4m2 8m 9 0?

✰ Solution :-

∴ Quadratic equation have non - real roots.

How do you describe the nature of the roots of 3x² 4x 5 0?

Imaginary roots. Also the discriminant is b² - 4ac = -44 < 0. Thus we have imaginary roots. Therefore, the best description of the roots of the equation 3x² - 4x + 5 = 0 is imaginary roots.

How do you find the roots of a quadratic equation in Class 10?

Based on the value of the discriminant, D=b²−4ac, the roots of a quadratic equation, ax² + bx + c = 0, can be of three types. Case 1: If D>0, the equation has two distinct real roots. Case 2: If D=0, the equation has two equal real roots. Case 3: If D<0, the equation has no real roots.

What is the nature of the roots of the quadratic equation 3x2 +2 0?

1 Answer. Hence, the given equation has real and equal roots.

What are the real roots of the equation x2 3 x1 3 2 0?

Solution. Hence, roots are -8, 1.

For what value of k are the roots of the quadratic equation 3x 2 2kx 27 0?

∴ k=±9.

What is the nature of the roots of the quadratic equation 4x²8x 9 0?

Therefore, Quadratic equation has no real roots.

Which of the following is one of the roots of the quadratic equation 5x2 12x 9 0?

As a result, the correct answer is x=-3/5 and x=3.

What is the value of k for which the quadratic equation 3x2 KX k 0 has equal roots?

When k = 0 or k = 12, 3x² - kx + k = 0 will have equal roots.

What is the nature of the roots of the quadratic equation 2x² 3x 4 0 real real and equal real and unequal?

Answer: The roots are real and distinct.

What is the discriminant of 2x2 6x 3 0?

iii) 2x² - 6x + 3 = 0. b² - 4ac is called the discriminant of the quadratic equation and we can decide whether the real roots exist or not based on the value of the discriminant. Hence the equation has no real roots. Hence the equation has two equal real roots.

Which of the following is the value of the discriminant of the quadratic equation 2x 2 3x 5 0?

Summary: The discriminant of the quadratic equation 2x² + 3x - 5 = 0 is 49.

What is the nature of the roots of the quadratic equation 5x2 3x?

Answer. Since D < 0. Hence, roots are imaginary and distinct.

How do I find the roots of a quadratic equation?

To find the roots of a quadratic equation ax² + bx + c = 0 by completing square, complete the square on the left side first. Then solve for x by taking the square root on both sides.

How do you find the alpha and beta of a quadratic equation?

Thus, if a quadratic has two real roots α,β, then the x-coordinate of the vertex is 12(α+β). Now we also know that this quantity is equal to −b2a. Thus we can express the sum of the roots in terms of the coefficients a,b,c of the quadratic as α+β=−ba.