What are the real roots of the equation x2 3 x1 3 2 0?

Hence, the real root of the given equation are 1 & −8.

What are the real roots of the equation x2 3 x1 3 − 2?

Solution. Hence, roots are -8, 1.

How do you find the real roots of an equation?

What are the roots of the equation x² 3x m/m 3 0?

Solution. The given quadratic equation is x² − 3x − m (m + 3) = 0. Thus, the roots of the given quadratic equation are −m and m + 3.

What are real roots in quadratic equation?

Discriminant. For an equation ax²+bx+c = 0, b²-4ac is called the discriminant and helps in determining the nature of the roots of a quadratic equation. If b²-4ac > 0, the roots are real and distinct. If b²-4ac = 0, the roots are real and equal. If b²-4ac < 0, the roots are not real (they are complex).

The real roots of the equation x2/3 + x1/3 -2 = 0 are

Is 0 A real root?

When the discriminant is equal to 0, there is exactly one real root. When the discriminant is less than zero, there are no real roots, but there are exactly two distinct imaginary roots. In this case, we have two real roots.

For what values of k the roots of the equation x² 4x K 0 are real?

Solution. ∴ k has all real values k ≤ 4.

What is the nature of roots of the quadratic equation 4x2 − 12x − 9 0?

What is the nature of roots of the quadratic equation 4x² – 12x – 9 = 0? Since D > 0, therefore, roots of the given equation are real and unequal.

Which of the following is a possible value of k in x2 KX 4 0 if it has real and equal roots?

Therefore, k=±4.

What are real roots?

The real roots are expressed as real numbers. Suppose ax² + bx + c = 0 is a quadratic equation and D = b2 – 4ac is the discriminant of the equation such that: If D = 0, then the roots of the equation are real and equal numbers. If D > 0, then the roots are real and unequal.

How do you find two real roots?

For the quadratic equation ax2 + bx + c = 0, the expression b2 – 4ac is called the discriminant. The value of the discriminant shows how many roots f(x) has: - If b2 – 4ac > 0 then the quadratic function has two distinct real roots. - If b2 – 4ac = 0 then the quadratic function has one repeated real root.

How many real roots are there?

When you solve for the roots of a quadratic equation, there are several possible outcomes. You can have two real number solutions. If you set x equal to either solution, the result with be zero both times. There can be just one real number solution.

How many real roots does the equation x² 3x 2 0 have?

Step-by-step explanation:

Hence the given quadratic equation has two distinct real roots, because discriminant is greater than 0. Hence the root of quadratic equation x2−3x−2=0 are x=3+√172andx=3−√172. Therefore, number of real roots is 4.

How many solutions does the equation 2x 3 have if M 0?

so there are three solutions of the given equation.

Which of the following is not a quadratic equation?

option B is a linear equation, not a quadratic equation.

What is the nature of roots of the quadratic equation 2x2 3x 4 0?

Answer: The roots are real and distinct.

What is the nature of roots of the quadratic equation 2x2 √ 5x 1 0?

Hence, the roots of the quadratic equation 2x² – √5x + 1 = 0 are imaginary.

Which of the following is one of the roots of the quadratic equation 5x2 12x 9 0?

As a result, the correct answer is x=-3/5 and x=3.

For what value of k the roots of equation 3x2 10x K 0 are reciprocal of each other?

Answer: The value of k is 3.

For what value of k are the roots of the quadratic equation K 4 x2 +( K 4x 4 0?

Therefore, the value of K for which the roots of the given equation is equal is 6.

How do you find the roots or solutions of a quadratic equation?

You can find the solutions, or roots, of quadratic equations by setting one side equal to zero, factoring the polynomial, and then applying the Zero Product Property. The Principle of Zero Products states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0.

Which equation has no real roots?

A quadratic equation ax² + bx + c = 0 has no real roots if discriminant < 0. Hence option A is the answer.

What are real and non real roots?

When a, b, and c are real numbers, a ≠ 0 and the discriminant is positive but not a perfect square then the roots of the quadratic equation ax² + bx + c = 0 are real, irrational and unequal. Here the roots α and β form a pair of irrational conjugates.

How do you find all real roots of a polynomial?

You can find the roots, or solutions, of the polynomial equation P(x) = 0 by setting each factor equal to 0 and solving for x. Solve the polynomial equation by factoring. Set each factor equal to 0.