How many terms of the AP 9 17 25 Dotdotdot must be taken to get a sum of 450?

So, we can conclude that 10 terms must be taken from a given A.P to get the sum as 450.

How many terms of an AP 9 17/25 must be taken to given a sum of 636?

So we have to take 12 terms in an A.P to give a sum of 636. So n = 12 is the required answer. Note: Whenever we face such types of problems it is advised to have a good grasp over the general formula related to that specific series which is being asked of in the question, just like arithmetic progression in this case.

How many terms is the AP are needed to make the sum?

Hence, the number of terms is 12.

How many terms of an AP must be taken for their sum to be equal to 120?

Since number of terms should be a whole number .

How many terms of the AP 27 24 21 should be taken so that their sum is zero?

We have to find the number of terms that must be taken so that their sum is zero. Let the number of terms to be taken be . The number of terms to be taken is 19.

How many terms of the AP. 9,17,25.... must be taken to give a sum of 636?

How many terms of the AP 22 2018 should be taken so that their sum is zero?

Answer: 23 terms of the AP should be taken so that their sum is zero .

Which term of the AP 27 24 21 is?

Solution: The term of the A.P. which is 0 is 10th.

How many terms of the AP 9 17/25 must be taken to give a sum of 596?

12 terms must be taken for AP.

How many terms of an AP must be taken for their sum to be equal to 91?

∴ We need 7 terms to get a sum of 91.

How many terms of an AP must be taken for their sum to be equal to 200 if its third term is 16 and the difference between the 6th and the 1stterm is 30?

1 Answer. Explanation: If the difference between the 6th and the 1st term is 30, it means that the common difference is equal to 6. Since, the third term is 16, the AP would be 4, 10, 16, 22, 28, 34, 40, 46 and the sum to 8 terms for this AP would be 200.

How many terms of AP 24 2016 must be taken so that the sum may be 72 explain the double answer?

Hence 4 terms or 9 terms add up to 72.

How many terms of AP are needed to the sum 25?

So either 5 terms or 20 terms of the AP will add up to -25.

How many terms of the AP are needed to give the sum 25?

<br> Thus, 5 terms are needed to give the sum `-25.

How many terms of the AP 17 /15/13 must be added to get the sum 72?

So we can see that the sum of 6 terms and sum of 12 terms is 72.

How many terms of the AP 54 51 48 are needed to give the sum 513 explain the double answer?

Answer : Hence, the sum of 18 terms of the given AP is 513.

How many terms of the AP 16 14 12 are needed to give the sum 60?

Hence, the number of terms are 5 or 12.

How many terms of the AP 63 60 57 54 must be taken so that their sum is 693 explain the double answer?

Solution. The given AP is 63, 60, 57, 54,……….. So, the sum of 21 terms as well as that of 22 terms is 693.

How many terms of the AP 20 19⅓ 18⅔ must be taken so that their sum is 300 explain the double answer?

Hence, the sum of 25 terms as well as that of 36 terms is 300.

How many terms of an AP must be taken for their sum to be equal to 120 if its third term is 9 and 3 the difference between the seventh and second term is 20?

So sum of 8 terms of the AP =120.

How many terms are there in the AP?

Thus, there are 27 terms in the given A.P. Concept: Arithmetic Progression (A.P.)

How many terms of an AP 45 39 33 must be taken so that their sum is 180 explain the double answer?

We have to find the number of terms that must be taken so that their sum is 180. Solution: Let the number of terms be . The number of terms to be taken is 6 or 10.

How many terms of the AP 21 18 15 must be added to get the sum 0?

Hence, 15 terms of the AP must be added to get the sum 0.

Which term of the AP 27 24 21 Is zero 2 points a 8th B 10th c 9th D 11th?

So, 0 is the 10th term of the AP.

Which term of the AP 8 14 20/26 will be 72 more than its 41st term?

53th term of AP will be 72 more than its 41th term. Was this answer helpful?

What is the 21st term of an AP whose first two terms are 3 and 4?

The 21^st term of the AP whose first two terms are –3 and 4 is 137. Explanation: First two terms of an AP are a = – 3 and a_{2 =} 4.