How many 3 digits numbers can be formed from the digits 1 2 3 4 6 If the digits can be repeated?

Problem 2: How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated? Solution: Answer: 108.

How many three digit number can be formed from the digits 1,2 3 and 4 if the digits can be used only once?

But there are 4 different numbers. So the number of 3-number combinations are- (1,2,3),(1,2,4),(1,3,4),(2,3,4). Each can be arranged in 6 ways, so we get 24 ways totally.

How many even 3-digit numbers can be formed from the digits 1/2 5/6 and 9 without repeating any digits?

Correct Option: D

(4 - 2)! Total ways = 3 × 4 × 2 = 24 ways. {∵ Total available digits are 1, 2, 5, 6, 9.

How many numbers can be formed using all the digits 1,2 3 4 3 2 1 such that even digits always occupy even places?

Expert-verified answer

We can form 7 digits numbers.

How many 3-digit numbers can be formed from the digits 1,2 3 if repetition is allowed?

Answer: 125

As repetition is allowed, So the number of digits available for B and C will also be 5 (each).

How many 3 digit numbers can be formed using digits 4,5,6,7,8 if digits repeated, not repeated

How many 3 digit numbers can be formed with the digits 1,2 3 4 5 repetition of digits not allowed?

Problem 2: How many 3-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 if the digits can be repeated? Solution: Answer: 108. Let 3-digit number be XYZ.

How many three digit numbers can be formed using the digits 0 1 3 5 6 7 If I repetition of digits is not allowed II repetition of digits is allowed?

Therefore, a total of 100 3 digit numbers can be formed using the digits 0, 1, 3, 5, 7 when repetition is allowed.

How many numbers can be formed using all of the digits 1/2 and 3 exactly once?

Originally Answered: How many 3-digit numbers can be formed using only1, 2, 3? This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .

How many numbers can be formed with the digits 2 3 4 5 4 3 2 so that the odd digits occupy the odd places?

Required number of numbers =(3×6)=18.

How many numbers can be formed by using all the digits 1 2 3 4?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120. Now, in half them unit's digit will be bigger than the ten's digit and in half of them it will be smaller.

How many 3 digit numbers can be formed using the digits 2 3 4 and 5 as often as desired?

I was able to get this question, by changing 2, 3, 4 and 5 to 1, 2, 3 and 4; then multiplying 4 by 3 by 2 to give 24 possibilities.

How many 4 digit numbers can be formed from 1 2 3 4 and 5 if repetitions are not allowed?

Answer. 120 numbers. Case:2 when repetition is allowed.

How many 3 digit numbers can be formed from the digits 2 3 5 6 and 7 which are divisible by 4 and none of the digits is repeated?

∴ Required number of numbers = (1 x 5 x 4) = 20.

How many three digit multiples of 3 can be written using numbers 1 3 5 9 of all digits are different?

Answer: 195, 531, 591, 135, 315, 351 etc.

How many numbers can be formed with the digits 1 6 7 8 6 1 so that the odd digits always occupy the odd places?

Total ways = 2 * 9 = 18 ways.

How many 7 digit numbers can be formed using the digits?

Hence, the required number of 7 digit numbers = 420 - 60 = 360.

How many three digit odd numbers can be formed by using the digits 1,2 3 4 5 6 If I the repetition of digits is not allowed II the repetition of digits is allowed?

How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed. = m x n x p = 5 x 4 x 3 = 60.

How many 3 digit numbers can be formed using the digits 0 1 2 and 5 if repetition of digits is not allowed?

The different 3-digit numbers which can be formed by using the digits 0, 2, 5 without repeating any digit in the number are 205, 250, 502 and 520. Therefore, four 3 digit numbers can be formed by using the digits 0, 2, 5.

How many 3 digit numbers can be formed by using the digits 1 to 9 if digits can be repeated?

⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504.

How many numbers can be formed from the digits 1 3 5 9 if repetition of digits is not allowed?

Hence, 64 numbers can be formed.

How many four digit numbers can be formed using the digits 2 3 5 1 7 9 <UNK> repetition of digits is not allowed?

Hence, there are 720 numbers can be formed.

How many numbers of up to 5 digits can be created using the digits 1 2 3 and 5 each at least once such that they are a multiple of 15?

There are 12 possibilities overall. The question is "How many numbers of up to 5 digits can be created using the digits 1, 2, 3 and 5 each at least once such that they are a multiple of 15?"

How many four digit numbers divisible by 5 are formed using the digits 0 1 3 5.7 9 if repetition is not allowed and digits are not placed next to each other?

So there are 36 numbers satisfying the given criteria.

How many 3 digit numbers can be formed from the digits 2 3 5 6 7 and 9 which are even and none of the digits is repeated?

∴ 3 - digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9 is 20.