How many 3 digit numbers can be formed using the digits 0 1 2 and 5 if repetition of digits is not allowed?

The different 3-digit numbers which can be formed by using the digits 0, 2, 5 without repeating any digit in the number are 205, 250, 502 and 520. Therefore, four 3 digit numbers can be formed by using the digits 0, 2, 5.

How many 3 digit numbers can be formed if no repetition is allowed?

There are 504 different 3-digit numbers which can be formed from numbers 1, 2, 3, 4, 5, 6, 7, 8, 9 if no repetition is allowed. Note: We can also use the multiplication principle to answer this question.

How many 3 digit numbers can be formed from the digits 12345?

Thus, The total number of 3-digit numbers that can be formed = 5×5×5 = 125.

How many three digits number can be formed from the digits 0 1 2 3 and 4 assuming that 2 repetition of digits are not allowed?

Therefore 48 Three digit numbers are possible.

How many 3 digit even numbers are formed using the digits 0 1 2 9 if the repetition of digits is not allowed?

=328. Was this answer helpful?

Total 3 Digit Numbers If Repetition allowed

How many even 3 digit numbers can be formed from the digits 1/2 5/6 and 9 without repeating any digits?

Correct Option: D

(4 - 2)! Total ways = 3 × 4 × 2 = 24 ways. {∵ Total available digits are 1, 2, 5, 6, 9.

How many 3 digit numbers can be made up from the even digits from 0 to 9 you can include numbers starting with a 0?

Therefore the number of three digit even numbers ending with 0 is 9(8) =72.

How many three digit numbers can be formed using the digits 0 1 3 5 6 7 If I repetition of digits is not allowed II repetition of digits is allowed?

Therefore, a total of 100 3 digit numbers can be formed using the digits 0, 1, 3, 5, 7 when repetition is allowed.

How many three digit numbers can be written from the digits 1 2 3 and 4 if repetition of digits is allowed?

But there are 4 different numbers. So the number of 3-number combinations are- (1,2,3),(1,2,4),(1,3,4),(2,3,4). Each can be arranged in 6 ways, so we get 24 ways totally.

How many 3 digit odd numbers can be formed from the digits 123456 if the digits can be repeated?

<br> Hence, by the fundamental principle of multiplication, the required number of odd numbers `= (3xx6xx6) = 108. `

How many 3 digit numbers can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits are repeated?

∴ Required number of numbers = (1 x 5 x 4) = 20.

How many 3 digit numbers can be formed using 2 3 4 and 5 with none of the digits being repeated?

Answer: There are 24 three digits numbers.

How many three digit multiples of 3 can be written using numbers 1 3 5 9 of all digits are different?

Answer: 195, 531, 591, 135, 315, 351 etc.

How many three digit numbers can be formed from the six digits are 2 3 5 6 7 and 9 when repetitions of digits are not allowed?

a) There are six digits 2, 3, 5, 6, 7 and 9. Supposed repetition are not allowed. 120 three-digit numbers can be formed.

How many outcomes can we get if we are to select 3 numbers from 0 to 9 with repetition?

Thanks, Mike. Hi Mike. If order mattered, we would say select the first number (10 choices), then the second (9 choices) then the third (8 choices). So there would be 10 x 9 x 8 = 720 possible choices.

How many 3 digit numbers can be formed by using the digits 1 to 9 if digits can be repeated?

⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504.

How many numbers can be formed with the digits 1,2 3 4 3 2 1 so that the odd digits always occupy the odd places?

Expert-verified answer

We can form 7 digits numbers.

How many 3 digit numbers can you make using the digits 1/2 and 3 without repetition?

Answer: 24

So the number of digits available for B = 3 (As one digit has already been chosen at A), Similarly, the number of digits available for C = 2.

How many 3 digit numbers are there that have digits 1/2 and 3 each of them exactly once )?

Originally Answered: How many 3-digit numbers can be formed using only1, 2, 3? This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .

How many 3 digit numbers can be formed by using the digits 0 1 3 5 6 when the digits may be repeated any number of times?

<br> So, each can be filled in 5 ways. <br> ∴ the required number of numbers `=(4×5×5)=100.

How many four digit numbers can be formed using the digits 2 3 5 1 7 9 <UNK> repetition of digits is not allowed?

Hence, there are 720 numbers can be formed.

How many 3 digit natural numbers can be formed using no zero and at least one 7 in each number?

To obtain the number of 3 digit even numbers that do not contain 7, x has 8 options, while y has 9 options and z continues to have 5 options, i.e., 8×9×5=360. Hence, the number of 3 digit even numbers that contain at-least one 7 is 450−360=90.

How many 3-digit even numbers can be formed from the digits 0 1 2 3 4 and 5 when none of the digits are repeated?

Count the number of 3-digit strings whose last digit is even. This gives 60−8=52 3-digit even numbers using digits from {0,1,2,3,4,5} without repetition.

How many 2 digit numbers can be formed from the digits 3 5 7 and 9 if repetition is not allowed?

Summary: All possible two-digit numbers formed by using the digits 3, 7, and 9 if repetition of the digit is allowed are 33, 37, 39, 73, 77, 79, 93, 97, and 99.

How many 3 digit multiples of 18 have the sum of the digits is equal to 18?

Answer: 25 three-digit multiples of 18 have the sum of the digits also equal 18.