# How many 3 digit number can be formed from the digits?

As repetition is not allowed, So the number of digits available for B = 4 (As one digit has already been chosen at A), Similarly, the number of digits available for C = 3. Thus, The total number of 3-digit numbers that can be formed = 5 × 4 × 3 = 60.

## How many 3 digit numbers can be formed from the digits 12345?

Thus, The total number of 3-digit numbers that can be formed = 5×5×5 = 125.

## How many 3 digit numbers can be formed from the digits 1/2 and 3?

So I take some particular numbers, like 1,2,3 and say that, well, 1 can go in 3 places, 2 in 2 places and 3 in 1 place, so by multiplication principle, there are 6 ways of forming a 3-digit number with 1,2,3. But there are 4 different numbers. So the number of 3-number combinations are- (1,2,3),(1,2,4),(1,3,4),(2,3,4).

## How many three digits numbers can be formed using the digits 1 2 3 4 5 of digits Cannot be repeated?

Total Number of Numbers which can be formed by numbers 1,2,3,4,5 (without repeating digitsi) = 5*4*3*2*! = 5! = 120.

## How many 3 digit numbers can be formed using the digits 0 1 2 and 5 if repetition of digits is not allowed?

The different 3-digit numbers which can be formed by using the digits 0, 2, 5 without repeating any digit in the number are 205, 250, 502 and 520. Therefore, four 3 digit numbers can be formed by using the digits 0, 2, 5.

## How many 3 digit numbers can be formed by using the digits 1 to 9 if digits can be repeated?

⇒So, the required number of ways in which three-digit numbers can be formed from the given digits is 9×8×7=504.

## How many 3 digit numbers can be formed from the digits 2 3 5 6 7 and 9 which are divisible by 5 and none of the digits are repeated?

∴ Required number of numbers = (1 x 5 x 4) = 20.

## How many numbers can be formed with the digits 1 2 3 4 3 2 1 so that the odd digits always occupy the odd places?

We can form 7 digits numbers.

## How many 4 digit numbers can be formed from 1 2 3 4 and 5 if repetitions are not allowed?

Answer. 120 numbers. Case:2 when repetition is allowed.

## How many different numbers of four digits can be formed with the digits 2 3 4 5 6 7 None of the digits being repeated in any of the numbers so formed?

There is 3 possible ways to fill the first place of four digit number. ∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9. Stay updated with the Mathematics questions & answers with Testbook.

## How many 3 digit numbers can be formed using the digits 1 3 5 7 9 where we are allowed to repeat the digits?

Therefore, a total of 100 3 digit numbers can be formed using the digits 0, 1, 3, 5, 7 when repetition is allowed.

## How many numbers of five digits can be made with the digits 3/4 and 5 each of which can be used at most thrice in a number?

Therefore, there will be 60 distinct 5 - digit numbers.

## How many 3-digit numbers can be formed using the digits 0 9?

If what you want are all possible three digit numbers then you have 10 choices for the first digit, you have 10 choices for the 2nd digit,and you have 10 choices for the 3rd digit giving you 10x10x10 = 1000 in all.

## How many three digit multiples of 3 can be written using numbers 1 3 5 9 of all digits are different?

Answer: 195, 531, 591, 135, 315, 351 etc.

## How many 4 digits are formed using the digits 0 1 2 3?

Therefore the number of four digit numbers formed using 0, 1, 2, 3 is 18.

## How many 4 digit numbers can be formed using 4 digits?

Finally there are 4 choices for the last digit so the number of possible 4 digit numbers is 4 4 4 = 256.

## How many 4 digit codes can be formed from the digits 1 3 5 7 and 9 if repetition of digits is not allowed?

<br> Number of 4-digit numbers `=(4xx3xx2xx1)=24. ` <br> Hence, the number of required numbers `=(4+12+24+24)=64. ` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

## How many numbers can be formed with digits 1 2 3 4 3 2 1 the even digits always occupy the even places?

3. ` <br> Hence, the required number of numbers `=(6xx3)= 18.

## How many numbers can be formed with the digits 2 3 4 5 4 3 2 so that the odd digits occupy the odd places?

Required number of numbers =(3×6)=18.

## How many numbers can be formed using all of the digits 1/2 and 3 exactly once?

Originally Answered: How many 3-digit numbers can be formed using only1, 2, 3? This is because you have space for three digits that can be chosen from the set [1,2,3]. So you can make 27 three digit different numbers .

## How many three digit numbers can be formed from the six digits are 2 3 5 6 7 and 9 when repetitions of digits are not allowed?

a) There are six digits 2, 3, 5, 6, 7 and 9. Supposed repetition are not allowed. 120 three-digit numbers can be formed.

## How many 3 digit numbers can be formed without repeating?

n will be the number of digits that are not in 0, 2, 3, 4, 5 and 6. Hence 1, 7, 8, 9. The value of r will be 3, as we need a form 3 digit number only. Hence, 24 3-digits numbers can be formed without using the digits 0, 2, 3, 4, 5 and 6.

## How many 3 digit numbers can be formed using the digits 1 7?

If I have to use all three digits in each number, then there are 6 possible numbers: 137, 173, 317, 371, 713, and 731. A total of 27.