How did you find the center and radius of the circle given its equation?

In order to find the center and radius, we need to change the equation of the circle into standard form, ( x − h ) 2 + ( y − k ) 2 = r 2 (x-h)^2+(y-k)^2=r^2 (x−h)2​+(y−k)2​=r2​, where h and k are the coordinates of the center and r is the radius.

How do you find the center of a circle with an equation?

If the equation of a circle is given, then we can find its radius and center by comparing it with the general form of the equation: (x - h)² + (y - k)² = r². We will find the values of h, k, and r. Then, (h, k) will be the coordinates of the center of circle and r will be the radius.

How do you find the center and radius of a circle given its equation and vice versa?

The center and the radius of the circle can be found given the equation. To do this, transform the equation to its standard form. Remember that the equation will be (x-h)2 + (y-k)2 =r2 if the center is (h, k), or x2 + y2 =r2 if the center of the circle is at the origin.

How do you find the radius of a circle?

Radius of a circle from area: if you know the area A , the radius is r = √(A / π) . Radius of a circle from circumference: if you know the circumference c , the radius is r = c / (2 * π) .

What is the equation of the given circle?

The standard equation of a circle is given by: (x-h)² + (y-k)² = r². Where (h,k) is the coordinates of center of the circle and r is the radius.

How to find the center and radius of a circle in standard form

What is the general form of the equation of the given circle with center A?

Standard form for the equation of a circle is (x−h)2+(y−k)2=r2. The center is (h,k) and the radius measures r units.

How do you find the center and radius from standard form?

The standard form of a circle's equation is (x-h)² + (y-k)² = r² where (h,k) is the center and r is the radius. To convert an equation to standard form, you can always complete the square separately in x and y.

How will you find the radius of the circle whose center is not at the origin?

To find the radius, we must use the distance formula, d=√(x2−x1)2+(y2−y1)2.

What is the general form of the equation of the given circle with center at a B?

The equation of a circle in general form is Ax2 + By2 + Cx + Dy + E = 0, where A = B ≠ 0. How do the coefficients C and D change as the center of the circle crosses over the x- and y-axes?

What is the center of the circle?

The center of a circle is the point equidistant from the points on the edge. Similarly the center of a sphere is the point equidistant from the points on the surface, and the center of a line segment is the midpoint of the two ends.

What is the center of a circle whose equation is x2 y2 12x 2y 12 0?

The center of the circle of the given equation is x² + y² - 12x - 2y + 12 = 0 is (6,1).

What is the center of the circle whose equation is x² y² )= 1?

1 Answer. Roy E. Center is (0,0) and radius is 1 .

What is the radius of a circle whose equation is x2 plus y2+ 8x minus 6y +21 equals zero?

The radius of a circle whose equation is x² + y² + 8x - 6y + 21 = 0 is 5units.

What is the center of a circle whose equation is x2 y2 4x 8y 11 0?

Summary: The center of the circle of the given equation is x² + y² + 4x - 8y + 11 = 0 is (-2, 4).

What is the center and radius of the circle *?

1 Expert Answer

(x-h)^2+(y-k)^2 = r^2, where ( h, k ) is the center and r is the radius.

How do you find the center of anything?

What is the general form of the equation of the given circle with center at a B and radius of length M?

The general form of the equation of a circle with center at (a, b) and radius of length m is x² + y² - 2ax - 2by + (a² + b² - m²) = 0.

How do you find the center of a circle in Class 11?

(i) Equation of circle having centre (h, k) and radius (x — h)² + (y — k)² = a². If centre is (0, 0), then equation of circle is x² + y² = a². (ii) When the circle passes through the origin, then equation of the circle is x² + y² — 2hx — 2ky = 0.

How do you find the center of a circle in a level maths?

The General Form of the equation of a circle is x² + y² + 2gx +2fy + c = 0. The centre of the circle is (-g, -f) and the radius is √(g² + f² - c). Given a circle in the general form you can complete the square to change it into the standard form. More on this can be found on the Quadratic Equations page Here.

Which explains how do you find the radius of a circle whose equation is in the form x2 y2 Z?

Which explains how to find the radius of a circle whose equation is in the form x2 + y2 = z? The radius is the square root of the constant term, z.

Which equation represents a circle with a center at (- 4 9 and a diameter of 10 units?

Summary: The equation which represents a circle with a center at (-4, 9) and a diameter of 10 units is (x + 4)² + (y - 9)² = 25.

Which equation represents a circle with a center at (- 3 and a radius of 6 units?

Summary: The equation that represents a circle with a center at (-3, -5) and a radius of 6 units is (x + 3)² + (y + 5)² = 36.

Which equation represents a circle that contains the point (- 2 8 and has a center at 4 0?

Equation x² + y² - 8x - 84 = 0 represents a circle that contains the point (-2, 8) and has a center at (4, 0).