Are all matrices orthogonal?

All identity matrices are orthogonal matrices. The product of two orthogonal matrices is also an orthogonal matrix. The collection of the orthogonal matrix of order n x n, in a group, is called an orthogonal group and is denoted by 'O'. The transpose of the orthogonal matrix is also orthogonal.
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Are all orthogonal matrices orthonormal?

According to wikipedia, en.wikipedia.org/wiki/Orthogonal_matrix, all orthogonal matrices are orthonormal, too: "An orthogonal matrix is a square matrix whose columns and rows are orthogonal unit vectors (i.e., orthonormal vectors)".
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Is every symmetric matrix orthogonal?

The amazing thing is that the converse is also true: Every real symmetric matrix is orthogonally diagonalizable. The proof of this is a bit tricky. However, for the case when all the eigenvalues are distinct, there is a rather straightforward proof which we now give.
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Are all diagonal matrices orthogonal?

Every diagonal matrix is orthogonal.
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How do you know if a matrix is orthogonal?

How to Know if a Matrix is Orthogonal? To check if a given matrix is orthogonal, first find the transpose of that matrix. Then, multiply the given matrix with the transpose. Now, if the product is an identity matrix, the given matrix is orthogonal, otherwise, not.
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Orthogonal matrices | Lecture 7 | Matrix Algebra for Engineers



Can a non square matrix be orthogonal?

In linear algebra, a semi-orthogonal matrix is a non-square matrix with real entries where: if the number of rows exceeds the number of columns, then the columns are orthonormal vectors; but if the number of columns exceeds the number of rows, then the rows are orthonormal vectors.
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Is normal matrix orthogonal?

An orthogonal matrix Q is necessarily invertible (with inverse Q1 = QT), unitary (Q1 = Q), where Q is the Hermitian adjoint (conjugate transpose) of Q, and therefore normal (QQ = QQ) over the real numbers. The determinant of any orthogonal matrix is either +1 or −1.
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How do you prove something is orthogonal?

Definition. We say that 2 vectors are orthogonal if they are perpendicular to each other. i.e. the dot product of the two vectors is zero.
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Are all eigenvectors orthogonal?

In general, for any matrix, the eigenvectors are NOT always orthogonal. But for a special type of matrix, symmetric matrix, the eigenvalues are always real and the corresponding eigenvectors are always orthogonal.
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What is the condition of orthogonality?

In Euclidean space, two vectors are orthogonal if and only if their dot product is zero, i.e. they make an angle of 90° (π/2 radians), or one of the vectors is zero. Hence orthogonality of vectors is an extension of the concept of perpendicular vectors to spaces of any dimension.
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Can non symmetric matrices be diagonalized?

Equivalently, a square matrix is symmetric if and only if there exists an orthogonal matrix S such that ST AS is diagonal. That is, a matrix is orthogonally diagonalizable if and only if it is symmetric. 3. A non-symmetric matrix which admits an orthonormal eigenbasis.
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Can a matrix be orthogonal but not orthonormal?

The rows of an orthogonal matrix are an orthonormal basis. That is, each row has length one, and are mutually perpendicular. Similarly, the columns are also an orthonormal basis. In fact, given any orthonormal basis, the matrix whose rows are that basis is an orthogonal matrix.
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What is the difference between orthogonal and orthonormal matrices?

A square matrix whose columns (and rows) are orthonormal vectors is an orthogonal matrix. In other words, a square matrix whose column vectors (and row vectors) are mutually perpendicular (and have magnitude equal to 1) will be an orthogonal matrix.
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How do you prove two matrices are orthogonal?

To determine if a matrix is orthogonal, we need to multiply the matrix by it's transpose, and see if we get the identity matrix. Since we get the identity matrix, then we know that is an orthogonal matrix.
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Are eigen values orthogonal?

A basic fact is that eigenvalues of a Hermitian matrix A are real, and eigenvectors of distinct eigenvalues are orthogonal.
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Are all symmetric matrices normal?

A real, symmetric matrix is Hermitian, so these matrices are also normal. A unitary matrix (Definition UM) has its adjoint as its inverse, and inverses commute (Theorem OSIS), so unitary matrices are normal. Another class of normal matrices is the skew-symmetric matrices.
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Are all normal matrices Hermitian?

is a normal matrix, but is not a Hermitian matrix.
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How do you create an orthogonal matrix?

We construct an orthogonal matrix in the following way. First, construct four random 4-vectors, v1, v2, v3, v4. Then apply the Gram-Schmidt process to these vectors to form an orthogonal set of vectors. Then normalize each vector in the set, and make these vectors the columns of A.
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What is the difference between orthogonal and perpendicular?

Perpendicular lines may or may not touch each other. Orthogonal lines are perpendicular and touch each other at junction.
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Why is orthogonality important?

The important thing about orthogonal vectors is that a set of orthogonal vectors of cardinality(number of elements of a set) equal to dimension of space is guaranteed to span the space and be linearly independent. If you have not covered this fact in class, you soon will.
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Can a unitary matrix be orthogonal?

A unitary matrix is a complex square matrix whose columns (and rows) are orthonormal. It has the remarkable property that its inverse is equal to its conjugate transpose. A unitary matrix whose entries are all real numbers is said to be orthogonal.
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Can an MXN matrix be orthogonal?

A matrix A is orthogonal if an only if the columns of A form an orthonormal basis. The product of orthogonal matrices is orthogonal. The inverse of an orthogonal matrix is orthogonal. The transpose of an m x n matrix A, denoted At, is the n x m matrix which contains in the i,j entry the j,i entry of A.
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Can non-square matrices be similar?

Definition (Similar Matrices) Suppose A and B are two square matrices of size n . Then A and B are similar if there exists a nonsingular matrix of size n , S , such that A=S−1BS A = S − 1 B S .
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